Math, asked by PayalMaity, 11 months ago

in a two digit numbers the digit at unit place is equal to the square of the digit at tens place. if 54 is added the number the digit iterchanged. find the numbers

Answers

Answered by kuruish37

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numbers are 39 and 93..

Attachments:

kuruish37: please mark as brainlist

Answered by amitnrw

Answer:

Step-by-step explanation:

Let say number xy

So value of number = 10x + y

As per question

y = x^2

Interchanged number = yx

Value of interchanged number = 10y + x

So as per question

10y + x = 10x + y + 54

9y - 9x = 54

y - x = 6

x^2 -x -6 = 0

x^2 -3x + 2x -6 = 0

x(x-3)+2(x-3) = 0

(x-3)((x+2)= 0

x = 3

y = 3^2 = 9

Number = 39

Interchanged number = 93

shreya32457: I think u should solve it via given conditions ....

amitnrw: @shreya what do u mean ?

shreya32457: Means read the question the condition given is of squaring the unit's place but I have taken regular ....nothing else

shreya32457: answer is right but according to the question.....its not right

amitnrw: You better read question again it says unit place digit = square of digit at tens place

shreya32457: Means u have to take tense place as x and tense place as x^2

shreya32457: see the answer below ur answer .... he hadn't given complete ans. but the method is correct

amitnrw: Method is same dear

amitnrw: What's ur doubt ?

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