In a two- digit , the digit at the units place is double the digit in the tens place. The number exceeds the sum of its digit by 18. Find the number.
Answers
Answered by
7
Answer :
- The number is 24
Given :
- In a two digit , the digit at the units place is double the digit in the tens place
- The number exceeds the sum of its digits by 18
To find :
- The number
Solution :
- Let the number at one's place be 2x
- Let the number at tens place be x
The number of the x will be
》10(x) + 1(2x)
》10x + 2x
According To Question ,
Given that, the number exceeds the sum of its digits by 18 so
Sum of digits = x + 2x = 3x then ,
》10x + 2x = 3x + 18
》12x = 3x + 18
》18 = 12x - 3x
》18 = 9x
》9x = 18
》x = 18/9
》x = 2
- The digit of ones place = 2x = 2(2) = 4
- The digit of tens place = x = 2
Now we have to find the number
》 10(x) + 1(2x)
》10(2) + 1(2 × 4)
》20 + 4
》 24
Hence , The number is 24
Answered by
72
Given :-
- In a two digit, the digit at the units place is double is double the digit in the tens place.
- The number exceeds the sum of its digit by 18.
To find :-
- Find the number ?
Solution :-
- Let the number at one's place be 2x
- Let the number at ten's place be x
• The number of the x will be
10( x ) + 1( 2x )
★
- According to the question,
• The number exceeds the sum of its digit by 80
- Sum of digits = x + 2x = 3x,
:10x + 2x = 3x + 18
:12x = 3x + 18
:18 = 12x - 3x
:18 = 9x
:9x = 18
:x =
:x =
:★
Hence,
- The digit of one's place = 2x = 2( 2 ) = 4
- The digit of ten's place = x = 2
V E R I F I C A T I O N :
- Find the number ?
:10( x ) + 1( 2x )
:10( 2 ) + 1( 2 × 4 )
:20 + 4
:★
Hence Verified !!
- The number is =
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