Question

in a two digits number tens place digit is half of the digits at unit place if 18 is subtracted from number digits are revised . what is the sum of the number and number obtained after interchange digits​

Answer 1

Answer:

Step-by-step explanation:

Solution :

Let ten's digit= =X

Unit's digit = 2x

Required Number = 10x + 2x = 12x On Interchanging the Digit's Number = 10

(2x) + x = 21x

According to The Question

12x +27 21x

→ 27 = 21x12x

→ 27 = 9x

→ 27/9 = x

⇒ 3 = x

Vol 67

Required Number = 12 × 3 = 36

Hence, the number required number is

36.