In a two digits number ,the digit at ten's place is double the digit at unit's palce. If the digits of the number are interchanged the new number so formed is 27 less than the original number Find the original number.
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Two digit number = 10x + y
ten's digit = x
unit digit = y
According to the question ,
x = 2y. -(1)
10y + x = 10x + y - 27
9y + 27 = 9x
y + 3 = x
y + 3 = 2y. ( x = 2y)
3 = y
x = 2y
x = 2*3
x = 6
Original number = 10x + y
= 10*6 + 3
=63
ten's digit = x
unit digit = y
According to the question ,
x = 2y. -(1)
10y + x = 10x + y - 27
9y + 27 = 9x
y + 3 = x
y + 3 = 2y. ( x = 2y)
3 = y
x = 2y
x = 2*3
x = 6
Original number = 10x + y
= 10*6 + 3
=63
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