in a two house 60 w electric bulb are lighted for 4 hours and 100w bulb for 5 hours everyday calculate the electric energy consumed in 30 days
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Answer: 44.4 kwh
Explanation:for bulb one
60 w for 4 hour in 2 house =60×8w per day
= 480w per day
In 30 day= 480 × 30
=14400 w
Change it into kwh= 14400/1000
= 14.4kwh
For other bulb
100w per day for 5 hours=100×5 w
Int two house = 100×5×2
=1000w per day
For 30 day = 1000×30
=30000w
Change in kwh= 30000/1000
= 30 kwh
Add both
= 30+14.4
= 44.4 kwh
{ We can say it 44.4 unit also}
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