Physics, asked by Anonymous, 8 months ago

in a two-phase generator is connected to two 90 load resistors. Each coil generates 120 V ac. A common neutral line exists. How much current flows through the common neutral line?​

Answers

Answered by Anonymous
4

Explanation:

There is 2 phase so voltage 120x120 = 14400.

2R = 90X90 = 8100.

I = V/R.

S0 = 14400/8100 = 1.77.

Answered by vanishasaxena09
0

Answer:

There is phase so voltage

=120×120=14400

2R=90×90=8100

I=V/R (formula)

I=14400/8100

I=178

Explanation:

hope you got it.

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