in a two-phase generator is connected to two 90 load resistors. Each coil generates 120 V ac. A common neutral line exists. How much current flows through the common neutral line?
Answers
Answered by
4
Explanation:
There is 2 phase so voltage 120x120 = 14400.
2R = 90X90 = 8100.
I = V/R.
S0 = 14400/8100 = 1.77.
Answered by
0
Answer:
There is phase so voltage
=120×120=14400
2R=90×90=8100
I=V/R (formula)
I=14400/8100
I=178
Explanation:
hope you got it.
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