Question

In a typical experiment, 14 g of iron on heating with oxygen gave 20g of iron (III) oxide 35 g of iron on heating with oxygen
gave 5 g of iron(III) oxide. Show that theses results correspond to the law of definite proportions​

Answer 1

Question - In a typical experiment, 14 g of iron on heating with oxygen gave 20g of iron (III) oxide 35 g of iron on heating with oxygen

gave 50 g of iron(III) oxide. Show that theses results correspond to the law of definite proportions.

Answer -

Answer - Given -

In experiment 1 -

Mass of iron - 14 gram

Mass of iron (III) oxide - 20 gram

In experiment 2 -

Mass of iron - 35 gram

Mass of iron (III) oxide - 50 gram

Find - To prove law of definite proportion.

Solution - In experiment 1 -

Mass of oxygen - 20 - 14

Mass of oxygen - 6 gram

Percentage of iron - 14/20*100

Percentage of iron - 70%

Percentage of oxygen - 6/20*100

Percentage of oxygen - 30%

In experiment 2 -

Mass of oxygen - 50 - 35

Mass of oxygen - 15 gram

Percentage of iron - 35/50*100

Percentage of iron - 70%

Percentage of oxygen - 15/50*100

Percentage of oxygen - 30%

Since, percentage of iron and oxygen, in iron (III) oxide formed in both the ways, is same, hence, it can be said that Law of Definite Proportions is followed.