Question

In a typical hydraulic press, a force of 20 N is exerted on small piston of area 0.050 m2. Force exerted by large piston on load if it has an area of 0.50 m2 will be

Answer 1

Answer:

200 N will be the force exerted

Explanation:

So, by Pascal's law we know,

$\frac{F1}{A1} = \frac{F2}{A2} \\\\\frac{20}{0.05} = \frac{F2}{0.5}\\ \\\frac{20 X 100}{5} = \frac{10F2}{5}\\\\\frac{20X100}{10} = F2\\ \\F2 = 200 N$