Question

In a unbalanced wheatstone bridge the potential between the galvanometer is not

zero. If the galvanometer resistance is 20Ω, what is the galvanometer current? Lets

take Voltage = 20V , P/Q ratio as 4, known resistance as 6Ω and unknown resistance

as 3Ω.​

Answer 1

Answer:

The balanced condition for Wheatstones bridge is

Q

P

=

S

R

as is obvious from the given values.

No, current flows through galvanometer is zero.

Now, P and R are in series, so

Resistance,R

1

=P+R

=10+15=25Ω

Similarly, Q and S are in series, so

Resistance R

2

=R+S

=20+30=50Ω

Net resistance of the network as R

1

and R

2

are in parallel

i=

R

V

=

50

6×3

=0.36 A.

Answered By

toppr

Answer 2

Answer:

The balanced condition for Wheatstones bridge is P/Q=R/S

as is obvious from the given values.

No, current flows through galvanometer is zero.

Now, P and R are in series, so

Resistance,R 1 =P+R

=10+15=25Ω

Similarly, Q and S are in series, so

Resistance R 2 =R+S

=20+30=50Ω

Net resistance of the network as R1 and R are in parallel

i= V/R

=6×3=50

=0.36 A.

hope it helps you dude .