in a unit cell A B C and D are present at corners all face centers 1/2 of total corners body center and one third of all edges centers respectively. Then formula of unit cell is
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Answer: A2B6C3D2
Explanation: No. of A atoms =8*1/8 =1
No. of B atoms =6*1/2=3
No. of C atoms= 1/2 *1/8*8 +1= 3/2 (C atoms are present at 1/2 of corners and body centre.)
No. of D atoms =1/3*1/4*12 = 1
Ratio of A:B:C:D = 1:3:3/2:1 =2:6:3:2
Therefore formula is A2B6C3D2.
Pls ask if any doubt.
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