in a unit test the number of those that passed and the number of those that failed were in the ratio of 3:1. Had 8 more appeared and 6 less passed, the ratio of passes to failures would have been 2:1. f
Find how many appeared?
Answers
Answer:
136 students
Step-by-step explanation:
Ratio of passed to failed is 3:1
Hence,
Let no. of students passed = 3x
and No. of students failed = x
Total number of students = 3x + x = 4x
We are given that had eight more appeared and 6 less passed the ratio of pass to fail would be 2:1
Eight more students => No. of students = 4x + 8
Six less passed => No. of passed students = 3x - 6
No. of failed students = No. of students - No. of passed students
=> No. of failed students = (4x + 8) - (3x - 6) = x + 14
Ratio of pass: fail = 2:1
=> (3x - 6)/(x + 14) = 2/1
=> 3x - 6 = 2(x + 14)
=> 3x - 6 = 2x + 28
=> 3x - 2x = 28 + 6
=> x = 34
The total number of students appearing = 4x = 4*34 = 136
Answer: 136 students appeared
Verification:
Total students = 136
No. of passed = 3*34 = 102
No. of failed = 34
If 8 more had appeared, no. of students would be 144
If 6 less had passed, no. of passed students = 102 - 6 = 96
No. of failed students = 144 - 96 = 48
Thus the ratio of passed to failed would be 96:48 = 2:1 √
Answer:
136 Students had appeared in the exam...