Math, asked by vaishnav19naik, 10 months ago


in a unit test the number of those that passed and the number of those that failed were in the ratio of 3:1. Had 8 more appeared and 6 less passed, the ratio of passes to failures would have been 2:1. f
Find how many appeared?​

Answers

Answered by venupillai
9

Answer:

136 students

Step-by-step explanation:

Ratio of passed to failed is 3:1

Hence,

Let no. of students passed = 3x

and No. of students failed = x

Total number of students = 3x + x = 4x

We are given that had eight more appeared and 6 less passed the ratio of pass to fail would be 2:1

Eight more students => No. of students = 4x + 8

Six less passed => No. of passed students = 3x - 6

No. of failed students = No. of students - No. of passed students

=> No. of failed students = (4x + 8) - (3x - 6) = x + 14

Ratio of pass: fail = 2:1

=> (3x - 6)/(x + 14) = 2/1

=> 3x - 6 = 2(x + 14)

=> 3x - 6 = 2x + 28

=> 3x - 2x = 28 + 6

=> x = 34

The total number of students appearing = 4x = 4*34 = 136

Answer: 136 students appeared

Verification:

Total students = 136

No. of passed = 3*34 = 102

No. of failed = 34

If 8 more had appeared, no. of students would be 144

If 6 less had passed, no. of passed students = 102 - 6 = 96

No. of failed students = 144 - 96 = 48

Thus the ratio of passed to failed would be 96:48 = 2:1 √

Answered by DipikaJoshi
0

Answer:

136 Students had appeared in the exam...

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