Question

in a van de Graaff type generator , the radius of sphere is 2m . the maximum potential of the sphere can be (given Em = 3* 10^6 V/m)

Answer 1

Explanation:

Em=Vm/r

3×10^6=Vm/2

Vm=6×10^6 V

Answer 2

Answer:

The maximum potential of the sphere can be $6\times 10^6~ V$.

Explanation:

Given the radius of sphere,  $r=2m$

The electric field strength, $E = 3\times 10^6 V/m$

A Van de Graaff generator is an electrostatic generator, wherein a moving belt accumulates charge on a metal structure thus creating a very high electric potential.    

The potential inside conducting spherical shell of radius R and charge q is $V=\frac{kq}{r}$

Rewriting the expression, $kq=Vr$                                       ...(1)

And its electric field strength is given by $E=\frac{kq}{r^2}$

Rewriting the expression, $kq=Er^2$                                      ...(2)

Comparing the equations (1) and (2), we get

$Vr=Er^2\implies V=Er$

$= 3\times 10^6 \times 2$

$= 6\times 10^6~ V$

Therefore, the maximum potential of the sphere can be $6\times 10^6~ V$.