Question

In a vernier callipers n divisions of its main scale match with (n+5) divisions on its vernier scale. Each division of the main scale is of x unit. Using the vernier principle, find the least count.

Answer 1

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Answer 2

Explanation:

GIVEN,

x MSD=(x+5) VSD

$vsd = \frac{x}{x + 5} \: msd$

Least cost=

$1 - \frac{x}{x + 5} = \frac{5}{x + 5} \times x = \frac{5x}{x + 5}$