Physics, asked by savi123godamune, 3 months ago

In a vernier callipers ten smallest divisions of the vernier scale are equal to nine smallest divisions of the main scale. If the smallest division of the main scale is half millimetre then vernier constant is

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Answered by DARKIMPERIAL
2

Answer:

Thus, 1 division on the main scale is equal to xm1=xm2=1/10=0.1 x m 1 = x m 2 = 1 / 10 = 0.1 cm. In calipers C1, 10 equal divisions on the Vernier scale are equal to 9 main scale divisions. Thus, 1 division on the Vernier scale of C1 is equal to xv1=9xm1/10=0.09 x v 1 = 9 x m 1 / 10 = 0.09 cm.

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