Question

In a vernier calllipers, if xMSD=yVSD, y is smaller than X and y,x € Z^+, then prove how to achieve smallest value of least count then y=(x-1)

Answer 1

Answer: The least count is .

Solution:The least count of Vernier can be calculated by dividing the length of each division on main scale with number of divisions in ‘Vernier scale’.Here MSD is “main scale division” and VSD is “Vernier scale division”.As it is given that n division of Vernier scale “coincide with (n-1) divisions” of main scale. Thus

least count = x ÷ (n-1)