Question

In a vessel, there are 10 liters of alcohol. An operation is defined as taking out five liters of what is present in the vessel and adding 10 liters of pure water to it. What is the ratio of alcohol to water after two operations ?

Answer 1

Answer:

The final concentration of alcohol in the vessel will be 1 : 5.

Step-by-step explanation:

To calculate the decreasing concentration ratio of alcohol, the formula that has been given below could be used.

Final concentration =  Initial concentration (1−$\frac{replacement quantity}{Final volume}$)

After the first operation in which 5 liters of alcohol was taken out and 10 liters of water was added to the vessel.

Final concentration  =  1×(1−10/15)

                                 =   1/3.

After the second operation in which another 5 liters of alcohol is taken out and 10 liters of water is added to it.

Final concentration  = 13×(1−10/20)

                                 =1/6

So, the final concentration at the end of two operations is 1:5.