Question

In a victor meyer experiment 0.6g of a volatile substance displaced 112ml of air at S.T.P.
find the molar mass of the substance.​

Answer 1

Answer:

Volume occupied by solute at NTP = Volume of air displaced at NTP = 112 ml

For volatile solute

$[tex] PV= </p><p> \frac{MRT}{times} </p><p>$[/tex]

At NTP, P=1atm,T=273K

$1∗ </p><p>1000</p><p>112</p><p> </p><p> = </p><p>m</p><p>0.23</p><p> </p><p> ∗0.0821∗273$

$m = 46.02 and V.D. = 23.01$