In a Victor Meyer's determination ,0.36g of volatile substance displaces air which measures 140 ml at STP. Calculate the vapour density and molecular weight of the substance(1 litre of H2 at stp STP weight 0.09g)
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The mass of the substance is 57.63 g and the Vapour density is 28.81 g/m^3.
Explanation:
Volume occupies by solute at NTP = Volume of air displaced at NTP = 140 ml
Since for volatile solute we have
PV = ω / m RT
We know that
P = 1 atm , T = 273 k at NTP.
Now
140 / 1000 = 0.36 / m x 0.0821 x 273
14 m / 100 = 8.069
14 m = 806.9
m = 806.9 / 14 = 57.63 g
Vapour density = mass / volume
Vapour density = 57.63 / 2 = 28.81 g / m^3
Hence the mass of the substance is 57.63 g and the Vapour density is 28.81 g/m^3
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The vapour density of a gas is 11.2 .calculate the volume occupied by 11.2 g of the has at NTP ?
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