Question

In a village Rampur a woman purchased a car for Rs 5,00,000.After using for some years she sold it to her friend for Rs 3,50,000. She said to her friend that when she had bought the new car, her age was three times of her son’s age and her husband‘s age was five years more than her age .Five year ago (from that day) her son was 1 6 of his father’s age. a) What was the age of her son when she purchased the car?

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Given:

Amount for which car was purchased = Rs 5,00,000

Amount for which car was sold = Rs 3,50,000

Woman's age = 3 × Son's age

Husband's age = 5 + Woman's age

Son's age - 5 = $\frac{1}{6}$ × (Father's age - 5)

To find:

Age of Son when car was purchased.

Solution:

Let woman's age be W, son's age be S and father/husband's age be F

$W=3*S...(1)$

$F=5+W...(2)$

Substituting equation (1) in equation (2)

$F=5+3S...(3)$

$S-5=\frac{1}{6}*(F-5)...(4)$

Substituting equation (3) in equation (4)

$S-5=\frac{1}{6}*(5+3S-5)$

$S-5=\frac{1}{6}*3S$

$S-5=\frac{S}{2}$

$S-\frac{S}{2} =5$

$\frac{S}{2} =5$

$S=10$

Age of son = 10 years.

Age of woman's son when she purchased her car was 10 years.