In a village there are 4400 registered voters. 63% of the registered voters could cast their votes, out of
which 252 votes were invalid. If only two candidates were contesting the election and the winning candidate
won by 10% votes, what is the number of votes cast in favor of the winning candidate ?
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Total number of registered voters = 4400
No. of people who could cast their votes = 63% of 4400
= 63/100 * 4400 = 2772
Valid votes out of this = 2772 - 252 = 2520
As 2 candidates contested and winner won by 10% votes, so winner got 55% and loser got 45% [ only way to allocate this scenario ]
So, 55% of 2520
= 55/100 * 2520 = 1386
therefore winning candidate got 1386 votes.
No. of people who could cast their votes = 63% of 4400
= 63/100 * 4400 = 2772
Valid votes out of this = 2772 - 252 = 2520
As 2 candidates contested and winner won by 10% votes, so winner got 55% and loser got 45% [ only way to allocate this scenario ]
So, 55% of 2520
= 55/100 * 2520 = 1386
therefore winning candidate got 1386 votes.
Answered by
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Solution:-
given by:-
》total regustered voters are = 4400
》voter could cast their votes = 63% of
》invalid votes = 252
》acourding to quetion:-
》total casting votes = 4400×63/100-252
》 = 2520 votes
》two candidates persentage is =100%
》opposite candidate win by 10% votes
》then ,
》both persentage are 55% and 45%
》we have,
》1st candidate recieved
》2520×55/100 = 1386 votes
》winning candidates got
1386 votes
i hope its help
given by:-
》total regustered voters are = 4400
》voter could cast their votes = 63% of
》invalid votes = 252
》acourding to quetion:-
》total casting votes = 4400×63/100-252
》 = 2520 votes
》two candidates persentage is =100%
》opposite candidate win by 10% votes
》then ,
》both persentage are 55% and 45%
》we have,
》1st candidate recieved
》2520×55/100 = 1386 votes
》winning candidates got
1386 votes
i hope its help
Golda:
percentage is the correct spelling.
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