Math, asked by 27praveen16p96jw1, 1 year ago

In a village there are 4400 registered voters. 63% of the registered voters could cast their votes, out of
which 252 votes were invalid. If only two candidates were contesting the election and the winning candidate
won by 10% votes, what is the number of votes cast in favor of the winning candidate ?

Answers

Answered by shivamdalmia
0
Total number of registered voters = 4400

No. of people who could cast their votes = 63% of 4400

= 63/100 * 4400 = 2772

Valid votes out of this = 2772 - 252 = 2520

As 2 candidates contested and winner won by 10% votes, so winner got 55% and loser got 45% [ only way to allocate this scenario ]

So, 55% of 2520

= 55/100 * 2520 = 1386

therefore winning candidate got 1386 votes.
Answered by Robin0071
0
Solution:-

given by:-

》total regustered voters are = 4400

》voter could cast their votes = 63% of

》invalid votes = 252

》acourding to quetion:-

》total casting votes = 4400×63/100-252

》 = 2520 votes

》two candidates persentage is =100%

》opposite candidate win by 10% votes

》then ,

》both persentage are 55% and 45%

》we have,

》1st candidate recieved

》2520×55/100 = 1386 votes

》winning candidates got
1386 votes

i hope its help

Golda: percentage is the correct spelling.
Robin0071: thnx for telling
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