Question

In a water molecule Hydrogen present 11.11 % and Oxygen present 88.88 %, In a Carbon dioxide molecule Carbon present in 27.27 % and Oxygen present in 72.72%, applying the low of reciprocal proportion find out the ratio of Carbon and Hydrogen present in a compound containing Carbon and Hydrogen.

Answer 1

Answer:

Methane and carbon dioxide, both contains carbon and hence, carbon may be considered as the third element. Now, let the fixed mass of carbon = 1 gm. Then,

the mass of hydrogen combined with 1 gm carbon in methane

=2575=13gm

and the mass of oxygen combined with 1 gm carbon in carbon dioxide

=72.7327.27=83gm

Hence, the mass ratio of hydrogen and oxygen combined with the fixed mass of carbon, r1=13:83=18 Now, the mass ratio of hydrogen and oxygen in water,

r2=11.1188.89=18

As r1 and r2 are same , the data is according to the law of reciprocal proportion.