Question

In a water molecule Hydrogen present 11.11 % and Oxygen present 88.88 %, In a Carbon dioxide molecule Carbon present in 27.27 % and Oxygen present in 72.72%, applying the low of reciprocal proportion find out the ratio of Carbon and Hydrogen present in a compound containing Carbon and Hydrogen.

Answer 1

Answer:

Solution

Methane and carbon dioxide, both contains carbon and hence, carbon may be considered as the third element. Now, let the fixed mass of carbon = 1 gm. Then,

the mass of hydrogen combined with 1 gm carbon in methane

`" "=25/75=1/3gm`

and the mass of oxygen combined with 1 gm carbon in carbon dioxide

`" "=72.73/27.27=8/3gm`

Hence, the mass ratio of hydrogen and oxygen combined with the fixed mass of carbon, `r_(1)=1/3:8/3=1/8` Now, the mass ratio of hydrogen and oxygen in water,

`" "r_(2)=11.11/88.89=1/8`

As `r_(1)" and "r_(2)` are same , the data is according to the law of reciprocal proportion.