In a water sample the concentration of dissolved oxygen is found to be 3.5 103 M. Express the dissolved oxygen content in ppm unit in the sample. The molar mass of O2 is 32 g mol
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Hey dear,
● Answer -
Dissolved oxygen content = 112 ppm.
● Explanation -
# Given -
Solvent = water
Solute = oxygen
M = 3.5×10^-3 M
# Solution -
Molality of solution is calculated by -
M = W2×1000 / M2W1
W2/W1 = M2 × M / 1000
W2/W1 = 32 × 3.5×10^-3 / 1000
W2/W1 = 112×10^-6
W2/W1 = 112 ppm
Therefore, dissolved oxygen content in water is 112 ppm.
Hope this helped you...
● Answer -
Dissolved oxygen content = 112 ppm.
● Explanation -
# Given -
Solvent = water
Solute = oxygen
M = 3.5×10^-3 M
# Solution -
Molality of solution is calculated by -
M = W2×1000 / M2W1
W2/W1 = M2 × M / 1000
W2/W1 = 32 × 3.5×10^-3 / 1000
W2/W1 = 112×10^-6
W2/W1 = 112 ppm
Therefore, dissolved oxygen content in water is 112 ppm.
Hope this helped you...
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