Math, asked by shreenathyarn, 8 months ago

In a wedding function there are total
*1000 Papad* and
*1000 Guests* are there.

If each Man get *4* papad,
each Woman get *3* papad and
each child get *1/2* papad.

Then how many men, women & children attended the wedding?​

Answers

Answered by AditiHegde
0

Given:

In a wedding function there are total  *1000 Papad* and  *1000 Guests* are there.

If each Man get *4* papad,  each Woman get *3* papad and  each child get *1/2* papad.

To find:

Then how many men, women & children attended the wedding?​

Solution:

Let "x" be the number of men attending the wedding.

Let "y" be the number of women attending the wedding.

Let "z" be the number of children attending the wedding.

From given, we have,

x + y + z = 1000 ..........(1)

4x + 3y + z/2 = 1000  ..........(2)

multiply (2) by "2", we get,

x + y + z = 1000 ..........(1)

8x + 6y + z = 2000  ..........(3)

solving (1) and (3), we get,

7x + 5y = 1000

5y = 1000 - 7x

y = (1000 - 7x)/5

Now, we need to take the values of x such that, the y value also results in an integer form.

when x = 25, y = 165

using equation (1), we get,

25 + 165 + z = 1000

z = 1000 - 165 - 25

z = 810

x = 50, y = 130

using equation (1), we get,

50 + 130 + z = 1000

z = 1000 - 50 - 130

z = 820

x = 100, y = 60

using equation (1), we get,

100 + 60 + z = 1000

z = 1000 - 100 - 60

z = 840

Therefore, on an average, 25 men, 165 women and 810 children attended the wedding.

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