In a wire of circular cross-section with radius r free electrons travel with a drift velocity v, when a current I flows through the wire. The current in wire of half the radius and of the same material when the drift velocity is 2v
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Answer:
current become half
Explanation:
I=nAeV
V=drift velocity
A=area of cross section
A'= π(r/2)^2=πr^2/4
A'=A/4
V'=2V
I'= nA'eV'
I'= n(A/4)e(2V)
I'=1/2nAeV
I'=1/2I
so current become half
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