Question

) In a workshop a worker measures the length
of a steel plate with a Vernier callipers
having a least count 0.01 cm. Four such
measurements of the length yielded the
following values: 3.11 cm, 3.13 cm, 3.14
cm, 3.14 cm. Find the mean length, the
mean absolute error and the percentage
error in the measured value of the
length.
[Ans: 3.13 cm,
0.01 cm, 1.3%)​

Answer 1

Answer:

3.13 cm 0.01 cm 1.3 %

Explanation:

To get the mean length we usually add the values given then we divide them by the number of values given

Like in this case we have four values therefore

We add them then we divide by four

3.11 + 3.13 + 3.14 + 3.14 =12.52 cm

We then divide it by four

12.52 cm÷4 = 3.13cm

The mean absolute error is 0.01cm because it is the leat count

To calculate percentage error we first find the relative error

0.01÷3.13 = 0.031 cm

We then multiply the absolute error by 100 %

0.031 cm × 100 % = 3.1 %

Answer 2

Refer to the attachment above for your answer✔✔✔