In a workshop. There are five machines and the probability of any one of them to be out of
service on a day is
if the probability that at most two machines will be out of service
on the same day is (3/4)^k { then k is equal to:
Answers
Answered by
0
Answer:Given n=5,p=
4
1
,q=1−p=
4
3
Required probability
= when no machine has fault + when only one machine has fault + when only two machine has fault
=
5
C
0
(
4
3
)
5
+
5
C
1
(
4
1
)(
4
3
)
4
+
5
C
2
(
4
1
)
2
(
4
3
)
3
=
1024
243
+
1024
405
+
1024
270
=
512
459
=(
4
3
)
3
×k=(
4
3
)
3
×
8
17
by comparing we get
k=
8
17
Step-by-step explanation:
Answered by
0
Answer:
Hey mate here is ur answer....
Plz mark as brainlist....
Step-by-step explanation:
the probability is 1/5
the probability of at most two machines are 1/5
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