Question

In a workshop. There are five machines and the probability of any one of them to be out of
service on a day is
if the probability that at most two machines will be out of service
on the same day is (3/4)^k { then k is equal to:

​

Answer 1

Answer:Given n=5,p=  

4

1

​  

,q=1−p=  

4

3

​  

 

Required probability

= when no machine has fault + when only one machine has fault + when only two machine has fault

=  

5

C  

0

​  

(  

4

3

​  

)  

5

+  

5

C  

1

​  

(  

4

1

​  

)(  

4

3

​  

)  

4

+  

5

C  

2

​  

(  

4

1

​  

)  

2

(  

4

3

​  

)  

3

 

=  

1024

243

​  

+  

1024

405

​  

+  

1024

270

​  

 

=  

512

459

​  

 

=(  

4

3

​  

)  

3

×k=(  

4

3

​  

)  

3

×  

8

17

​  

 

by comparing we get

k=  

8

17

​

Step-by-step explanation:

Answer 2

Answer:

Hey mate here is ur answer....

Plz mark as brainlist....

Step-by-step explanation:

the probability is 1/5

the probability of at most two machines are 1/5