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Answer:
Explanation:
What is the volumeet the common factor for the base radii be x and the common factor for the heights be y.
Therefore,
r1 = 2x.
r2 = 3x
h1 = 5y
h2 = 3y
Volume of cylinder = pi * (r^2) * h
Therfore,
Ratio of their volumes =
(pi * (r1^2) * h1)/(pi * (r2^2) * h2)
(((2x)^2) * 5y)/(((3x)^2) * 3y)
(4 * (x^2) * 5y)/(9 * (x^2) * 3y)
(20 * (x^2) * y)/(27 * (x^2) * y)
20/27
OR
20:27
1K viewsView 2 Upvoters
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Vikas Rathore, Mankind from Earth
Answered February 4, 2017 · Author has 96 answers and 144.8K answer views
Volume of a cylinder=πr^2h
So,it is given that
Radius of smaller cylinder/ radius of bigger cylinder= 2/3
Therefore,radius of smallest cylinder=2x
Radius of bigger cylinder=3x
Also,
Height of smaller cylinder/ height of bigger cylinder=5/3= 5y/3y.
Now,ratio =
π (2x)^2 (5y) /π (3x)^2 (3y)
=5(4x^2)/3(9x^2)
=20/27
20:27
978 viewsView 2 Upvoters
Srinivasan, former Maths B.T.Asst Teacher (Retired) at P.S.G Sarvajana Hr.Sec School (1999-2010)
Answered February 4, 2017 · Author has 2.6K answers and 1.8M answer views
Let the radius and height of the first cylinder is r 1, h 1 respectively.
Similarly for the second cylinder r 2, h 2.
π(r1)2∗h1:π(r2)2∗h2=22∗5:32∗3 [cancelling pi ]
4*5:9*3=20:27
105 viewsView 1 Upvoter
Hungenahalli Sitaramarao Badarinath, Ph.D. in Civil Engineering. Maths keeps one mentally active.
Answered January 10, 2018 · Author has 27.1K answers and 14.3M answer views
Let the two cylinders A and B be.
The radius and height of A are 2r and 5h, while that of B are 3r and 3h.
The volume of cylinder A = (pi)(2r)^2*5h = (pi)20 r^2*h …(1)
The volume of cylinder B = (pi)(3r)^2*3h = (pi)27 r^2*h …(2)
The ratio of the volumes of cylinders A to B is 20:27.
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Kimtee Goh, i am a mechanical engineer from UNIVERSITY OF MALAYA, MALAYSIA
Answered February 4, 2017 · Author has 4.6K answers and 1.9M answer views
v/V=πr²h/πR²H=(r/R)²(h/H)=(4/9)*(5/3)=20/27
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