Question

In a Young's double slit experiment distance between the slits is 1mm. The
fringe width is found to be 0.6 mm. When the screen is moved through a
distance of 0.25 m away from the plane of the slit, the fringe width becomes
0.75 mm. Find the wavelength of light used.​

Answer 1

Answer:

The answer will be 0.6×10^(−6) m

Explanation:

According to the problem the distance between the slits is given and let us consider it is d and the width of the fringe is also given and we will consider it as s

let λ be the wavelength

Let r be the distance between the slit and the screen

Now we know that, the fringe width s = λr/d

                 Therefore,    0.6 x 10^(-3) = λr/0.001....(1)

             and                   0.75×10^(−3) =  λ(r+0.25)/0.001 ...(2)

        0.75/0.6 = (r+0.25)/r = 1.25

=>  (r+0.25) = 1.25r

=> 0.25 = 0.25 r

=>r = 1

Hence putting the value in 1

0.6 x 10^(-3) = λ x 1/0.001

=> λ = 0.6×10^(−6) m

Answer 2

Answer:

follow the steps as show u will get the method