Question

In a Young's double slit experiment, light has a frequency of 6 x 1014 Hz. The distance between the centres
of adjacent bright fringes is 0.75 mm. If the screen is 1.5 m away then find the distance between the slits.
10.
In a Young's experiment, the width of the fringes obtained with light of wavelength 6000
will be the fringe width​

Answer 1

Answer:

velocity of light=wavelength x frequency

3×10

8

= wavelength x6×10

14

wavelength =

6×10

14

3×10

8

=5×10

−7

m

given distance between adjacent bright fringe =0.75mm=wavelength x D/d

where D is distance between slit and screen , d is the distance between two slit .

now ,

0.75×10

−3

=

d

(5×10

−7

×1.5)

d=

(7.5×10

−4

)

(7.5×10

−7

)

=10

−3

m

Explanation:

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