Question

In a Young's experiment, the distance between two slits is 0.2 mm. If the
wavelength of light used in this experiment is 5000 Å, then the distance of 3rd
bright fringes from central maxima will be
(A) 0.75
(B) 0.075
(C) 0.0075 (D) 0.057​

Answer 1

Answer:

complete the question dude ..

Answer 2

Complete question:

In a Young's experiment, the distance between two slits is 0.2 mm and distance between slits and screen is 2 m. If the  wavelength of light used in this experiment is 5000 Å, then the distance of 3rd  bright fringes from central maxima will be

Answer:

The distance of 3rd  bright fringes from central maxima is 1.5 cm

Explanation:

Let us consider the central maxima is at x = 0

The position of the 3rd maxima is given by the formula:

n = 3Dλ/d

Where,

D = Distance between slits and screen

d = Distance between two slits

Now, on substituting the values, we get,

n = (3 × 2 × 5000 × 10⁻¹⁰)/(0.2 × 10⁻³)

n = 1.5 × 10⁻³

∴ n = 1.5 cm