Question

in a Young's two slots experiment using ligh of wavelength 6000A°the slits were 0.4mm and distance of the slits to the screen was1.2m find the separation of fringes.
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Answer 1

Answer :

Wavelength of light = 6000Å

Distance b/w slits = 0.4mm

Distance b/w slits and screen = 1.2m

We have to find the separation of fringes or fringe width$.$

★ Fringe width is the distance between two maxima of successive order on one side of the central maxima. This is also equal to distance between two successive minima.

• β = λ D/d

Notice that it is directly proportional to wavelength and inversely proportional to the distance between the two slits.

By substituting the given values,

➝ β = λ D/d

➝ β = (6000×10‾¹⁰)(1.2)/(0.4×10‾³)

➝ β = 18 × 10‾⁴

➝ β = 1.8 mm