Question

⭐In a zero order reaction, 20% of the reaction completes in 10 sec. How much time it will take to complete 50% of the reaction?

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Answer 1

$\huge{\mathfrak{Question:-}}$

In a zero order reaction, 20% of the reaction completes in 10 sec. How much time it will take to complete 50% of the reaction?

$\huge{\mathfrak{Solution:-}}$

$\sf{For\;zero\;reaction,\;x=kt}$

$\sf{Where,}$

$\sf{x=decrease\;in\;concentration\;of\;reactant\;(mol\;dm^{-3})}$

$\sf{k=rate\;constant\;(mol\;dm^{-3}\;sec^{-1})}$

$\sf{t=time\;(sec)}$

$\sf{Also,for\;50\%\;completion\;of\;reaction,\;i.e.\;Half\;life\;of\;reaction,\;t_{\frac{1}{2}}=\frac{a}{2k}}$

$\sf{Where,}$

$\sf{a=initial\;concentration\;of\;reactant.}$

$\sf{Let\;a=100\;mol\;dm^{-3}\;and\;after\;20\%\;completion\;of\;reaction,\;x=20\;mol\;dm^{-3}.\;Now,}$

$\sf{k=\frac{20\;mol\;dm^{-3}}{10\;sec}}$

$\sf{k=2\;mol\;dm^{-3}\;sec^{-1}}$

$\sf{t_{\frac{1}{2}}=\frac{100\;mol\;dm^{-3}}{2\times 2\;mol\;dm^{-3}\;sec^{-1}}}$

$\boxed{\sf{t_{\frac{1}{2}}=25\;sec.}}$

Answer 2

according to the maths,(chapter percentage) it would be answer like this

=20%in 10 sec

=so 10% in 5 sec

=and 50%

=5×5

=25 sec answer is this