Chemistry, asked by swamipriksha, 1 month ago

In a zero order reaction, for every 10°C rise in temperature, the rate of reaction is doubled. If temperature is increased from 20°C to 80°C, then the rate of the reaction will become
O 48 times
O 128 times
O 64 times
O 32 times​

Answers

Answered by shraddhasurvase35
1

Answer:

Explanation:

In a zero-order reaction for every 10^(@) rise of temperature, the rate is doubled. If the temperature is increased from 10^(@)C to 100^(@)C, the rate of the reaction will become. Alternate method with every 10∘ rise in termperature rate becomes double . So,I′I=2(100-1010)=29=512times.

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