Question

In AABC, A= 75°, B = 40° and C = 65°, find the measures of angles of the triangle formed by joining the midpoints of the sides of AABC.​
ebkdkcysut​

Answer 1

Answer:

In AABC, A= 75°, B = 40° and C = 65°, find the measures of angles of the triangle formed by joining the midpoints of the sides of AABC.

ebkdkcysut

60

60

and 60

it's a equilateral triangle

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Answer 2

Answer:

In ΔABC,

∠A=50∘,∠B=60∘ and ∠C=70∘

D, E and F are the mid points of sides BC, CA and AB respectively

DE, EF and ED are joined

∵ D, E and F are the mid points of sides BC, CA and AB respectively

∴ EF || BC

DE || AB and FD || AC

∴ BDEF and CDEF are parellelogram

∴∠B=∠E=60∘ and∠C=∠F=70∘

Then ∠A=∠D=50∘

Hence ∠D=50∘,∠E=60∘ and ∠F=70∘