Math, asked by Cracoos, 1 year ago

In AABC, AB = 3cm; AC = 3cm A = 50° and B=?​

Answers

Answered by chachchuu
5

Answer:

65

B+C=180-50(AB=AC) so (B=C)

B=130/2=65

Answered by TheAstrophile
8

\huge\mathfrak{Answer}

Given: AB = 3 cm, AC = 3 cm, A = 50°

Angle B = Angle C (Since AB = AC; angles opposite to equal sides are equal.)

Using Angle Sum Property (Sum of all angles of a triangle is 180°)

Angle A + Angle B + Angle C = 180°

Angle A + 2 × Angle B = 180°

50 + 2 × Angle B = 180

2 × Angle B = 180 - 50

2 × Angle B = 130

Angle B = 130/2

Angle B = 65

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