Question

In AABC, AD is perpendicular to BC. If AB = 6 cm, BC = 10 em and
AC = 8 cm, find the area of AABC. Also, find the length of AD.
8 cm
10 cm

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Answer 1

Answer:

In △ABC, AD⊥BC, sinB=0.8, tanC=1, BD=9

In △ABD,

sinB=0.8

cos2B=1−sin2B=1−(0.8)2

cosB=(0.6)2

cosB=0.6

cosB=ABBD

AB=0.6BD

AB=0.69=15

Also, using Pythagoras theorem, 

AB2=AD2+BD2

152=92+AD2

AD=144

AD=12 cm

Now, In △ACD

tanC=1=BP=CDAD

AD=CD=12 cm

Using Pythagoras theorem,

AD2+CD2=AC2

122+122=

Answer 2

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