In AABC and APQR, ZABC = ZPQR,
seg BD and seg QS are angle bisectors.
If!(AD) _!(DC)
(PS) (SR)
Prove that AABC - APQR.
Answers
Answered by
9
Answer:
According to the problem,
In triangle ABC, BD is the angle bisector
Then AD/DC=AB/AC ---------(1)
Similarly, in triangle QPR, QS is the angle bisector
Then PS/SR=PQ/QR ----------(2)
Given that AD/PS=DC/SR
Substitute AD=(DC.PS)/SR
On solving, AB/AC=PS/SR
Therefore AB/AC=PQ/SR
The sides are proportional to each other. Hence the triangle ABC~ triangle QPR.
Similar questions