In AABC, D is the mid-point of BC, E is any point on AC. F is the point on BC such that AF || DE. If square root of area of AABC is 16 cm, then ar(ACEF) is
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Step-by-step explanation:
Using mid point theorem, A line segment joining the mid points of the two sides of the triangle, is equal to half the length of the third side.
D and E are the mid points. Hence,
DE=
2
1
AC
DE=
2
1
(6.4)
DE=3.2cm
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