In AABC, D is the mid-point of BC. Find the
length of BC.
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ADB and ADC are right angle triangle
so,
using Pythagoras (AB) ^2. = (AD) +( BD)
(13) ^2 = (12) ^2+ (BD)^2
169 = 144 + (BD)^2
169 - 144 = (BD)^2
25= (BD)^2
BD =√25
BD= 5
BD = DC
5cm =5cm
BC =10 cm
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