Question

In AABC, D is the midpoint of side AB. Line DE |
side BC. A-E-C. Prove that point E is the
midpoint of side AC.​

Answer 1

Step-by-step explanation:

so, AD = DB ...(1)

so, in triangle, ABC&ADE

∠BAC=∠DAE ...(common angle)

as DE||BC

so, ∠ADE=∠ABC

and ∠AED=∠ACB

so, tri(ADE)∼tri(ABC)

SO, AC = AE+EC=2AE

=> AE = (AC)/2