Math, asked by lakshamanasangihal, 1 month ago

In AABC,
DE || BC, AD = 3cm, BD = 9cm and AC = 18cm
the measure of AE is,
A, 4cm
B. 4.5cm
C 2.5cm
D.5cm​

Answers

Answered by CuriousRohan
1

b will be the answer

Answer:

mark me is the

Answered by cmayush56
1

Answer:

The answer is B. 4.5

Step-by-step explanation:

let us assume that AE be x

and EC be (18-x)

Now ( Basic proportionality theorem )

AD/DB = AE/EC

3 / 9 = x / 18-x

cross multiplication

9x = 3(18-x)

9x = 54 - 3x

12x = 54

x = 54 / 12

x = 4.5

x = AE = 4.5

-------------------

checking

EC = 18-4.5 = 13.5

AC = AE+EC

AC = 4.5+13.5 = 18 [hence proved].

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