In AABC,DE || ,BC
AD =X+10,
DB=4x+10, AE=x+6 and
EC =X +10
FIND X
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Answered by
1
Answer:
ANSWER
In Δ ABC, DE ∥ BC
∴
DB
AD
=
EC
AE
(By basic proportionality theorem)
⇒
x−2
x
=
x−1
x+2
⇒x(x−1)=(x+2)(x−2)
⇒x
2
−x=x
2
−4
⇒x=4.
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