Question

In AABC if BC = 3, CA =4, AB = 5 then cos angleBAC =





please explain ​

Answer 1

Answer:

Given a right triangle

with sides

BC= 3

AC= 4

AB= 5

we have to find cos of angle BAC

cos of ✓BAC = base/hypotenuse

base = AB = 5

hypotenuse = AC = 4

so cos of angle✓BAC = 5/4

hope it helps you ✌️✅✅✅