Question

In AABC, if (C = 90° and BC + CA = 23 cm and BC - CA = 7 cm, then find sin A + sin B.​

Answer 1

Answer:

Step-by-step explanation:

BC + CA =23

BC - CA = 7

On adding these equations we get

2BC = 30

BC = 15

Put this value in any one of the above equation and got value CA = 8

By using Pythagoras theorem we get

AB^2 = BC^2 + AC^2

AB^2 = 225+64 = 289

AB = √289 = 17

Now Sin A = BC/AB = 15/17

Sin B = AC/AB = 8/17

SinA + SinB= 15/17+8/17 =23/17 = 1.35