Question

In AABC, if ZB = 60°, ZC = 80° and the bisectors of angles ZABC and ZACB meet at a
point 0, then find the measure of ZBOC.​

Answer 1

Answer:

In △ABC,

∠ABC+∠ACB+∠BAC=180

∠ABC+70+50=180

∠ABC=60

∘

∠OCB=

2

1

(180−∠ACB)

∠OCB=

2

1

(180−50)

∠OCB=65

∘

∠OBC=

2

1

(180−∠ABC)

∠OBC=

2

1

(180−60)

∠OBC=60

∘

In △OBC,

∠OCB+∠OBC+∠BOC=180

65+60+∠BOC=180

∠BOC=180−125

∴∠BOC=55

Step-by-step explanation:

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