In AABC, is an isosceles triangle such that AB=AC and AD is median to BC. Which criteria we use to prove ABAD = ACAD?
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Answered by
2
Answer:
angles opposite to equal sides are equal
Step-by-step explanation:
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Answered by
0
Answer:
ab=ba
Step-by-step explanation:as ba =ab
so pq will also be ab and
hence its ab to bc
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