In AABC, prove that tan (A + B)/2 = cot C/2
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Answer:
In any traingle ABC,∠A+∠B+∠C=180
∘
⇒∠A+∠B=180∘ −∠C
⇒∠A+∠B÷2= 180° −∠C÷2
⇒ 2÷∠A+∠B=90∘ − 2÷∠C
⇒tan( 2÷∠A+∠B )=tan(90 ∘− 2÷∠C)
∴tan( 2
÷∠A+∠B )=cot 2÷∠C
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