In AABC right angled at B, if tan A= √3, then cos A cos C- sin A sin C - (A) - 1 (B) O (C) 1 (D) √3/2
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HERE U GO MATE
tan A= √3/1
by pythagoras theorem, find the missing side- hypotenuse ( ans=2)
* LHS - cosA x cos C = 1/2 x √3/2 = √3/2
now,
*RHS - sinA x sinC = √3/2 x 1/2 = √3/2
LHS - RHS
√3/2-√3/2= 0
THUS, YOUR ANSWER IS opt B ; 0
HOPE THIS HELPED...
PLS DO MARK ME AS A BAINLIEST..
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to simple please don't be confused
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