Question

In AABC right angled at B, sin C =5/13. Find: (1) sin A (ii) cos A (ii) cos C​

Answer 1

Answer:

Sin A =P/H = 12/13

Cos A = B/H = 5/13

Cos C =B/H = 12/13

Step-by-step explanation:

PLEASE FIND THE FULL ANSWER IN THE IMAGE ATTACHED

MAHIM SINGH